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A 35-pound force is applied to a 3-inch cylinder with a 6-inch stroke. What is the power produced by the cylinder that moves its full stroke in 0.7 s?

Respuesta :

MathPhys

Explanation:

Power = work / time

Power = force × distance / time

P = (35 lbf) (6 in) / (0.7 s)

P = 300 lbf in/s

lhmarianateixeira

The power produced by the cylinder that moves its full stroke in 0.7 s is 300 lbf in/s.

How to calculate power in watts?

In certain cases, you will find this formula written in the form W = A × V. For example, if the current is 3 amps (3A) and a voltage of 110V, simply multiply these two values ​​together to get the power of 330W (watts). The formula is P = 3A × 110V = 330 W (P being the power unknown).

So we have that:

[tex]Power = work / time\\Power = force*distance / time\\P = (35 lbf) (6 in) / (0.7 s)\\P = 300 lbf in/s[/tex]

See more about power at brainly.com/question/2289248

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