Respuesta :

Answer:

The cone's height is 9

Step-by-step explanation:

Recall that the volume of a cone is: [tex]\frac{h}{3} \pi \,r^2[/tex], where 'h' is the cone's height, and "r" the radius of its base.

In our case, we know that the volume of the cone equals; [tex]108\,\pi[/tex].

We also know the diameter of the base (12), so the radius of the base must be half of this: 6

Now we replace all known values in the formula for the volume, and solve for the unknown "h':

[tex]V=\frac{h}{3} \pi \,r^2\\108\,\pi =\frac{h}{3} \pi \,(6)^2\\108\,\pi =\frac{h}{3} \pi \,(36)\\108\,\pi =h (12) \pi \,\\h=\frac{108\,\pi }{12\,\pi } \\h=9[/tex]

The height of the cone will be "9".

Given values are:

  • Volume, V = 108 π
  • Base diameter, 12
  • Radius, r = 6

As we know the formula,

→   [tex]V = \frac{h}{2} \pi r^2[/tex]

By substituting the values, we get

[tex]108 \pi = \frac{h}{3} \pi\times (6)^2[/tex]

[tex]108 \pi = \frac{h}{3} \pi (36)[/tex]

[tex]108 \pi = h(12) \pi[/tex]

      [tex]h = \frac{108 \pi}{12 \pi}[/tex]

         [tex]= 9[/tex]

Thus the above response is correct.

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