A 62.7 kg weight-watcher wishes to climb a
mountain to work off the equivalent of a large
piece of chocolate cake rated at 617 (food)
Calories.
How high must the person climb? The
acceleration due to gravity is 9.8 m/s
2
and 1
food Calorie is 103
calories.
Answer in units of km.

Respuesta :

Correction

One food calorie is not 103 calories, rather, 1000 calories

Answer:

4.2 km

Explanation:

One food calorie is equal to 1000 calories and each calorie has 4.184 J hence for 617 food calories, the energy is equal to 617*1000*4.184

This energy is also given by mgh, the potential energy. M is the mass, g is acceleration due to gravity and h is height in metres.

Substituting 62.7 kg for m, 9.8 for g then

62.7*9.8h=617*1000*4.184

[tex]h=\frac {617*1000*4.184}{62.7*9.8}=4,201.2954464081m=4.2012954464081 km\approx 4.2 km[/tex]

The person must  climb "5299 m" high. To understand the calculation, check below.

Mass and Energy

According to the question,

Mass, m = 62.2 kg

Acceleration due to gravity, g = 9.8 m/s²

Cake's energy, E = 772 Calories or,

                            = 3.23 × 10⁶ J

We know the formula,

Potential energy, E = mgh

or,

The height, h = [tex]\frac{E}{mg}[/tex]

By substituting the values,

                       = [tex]\frac{3.23\times 10^6}{62.2\times 9.80}[/tex]

                       = [tex]\frac{3.23\times 10^6}{609.56}[/tex]

                       = 5299 m

Thus the above response is correct.  

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