Answer:
Therefore Cindy will catch Teri after 1 hour when she starts to walk.
Step-by-step explanation:
Assume after x hour Cindy will catch Teri.
Given that, Teri begins walking at 2 miles per hour at 1:00 pm.
Teri walks 30 minutes = 0.5 hour more than Cindy.
Teri walks (x+.5) hours.
We know that,
[tex]Distance=Time \times Speed[/tex]
The distance covered by Teri in (x+.5) hours is [tex]2 (x+.5)[/tex] miles.
The walking speed of Cindy is 3 miles per hour.
The distance covered by Cindy in x hours is [tex](3\times x)[/tex] = 3x miles.
Cindy and Teri both meet at a point. So both will walk same distance.
According to the problem,
[tex]2 (x+.5)=3x[/tex]
[tex]\Rightarrow 2x+1=3x[/tex]
[tex]\Rightarrow x=1[/tex]
Therefore Cindy will catch Teri after 1 hour when she starts to walk.
