Answer:
d. 200 and 2
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
Mean = 200
Standard deviation = 18
Sample size: 81
Standard error: [tex]s = \frac{18}{\sqrt{81}} = 2[/tex]
So the correct answer is:
d. 200 and 2
Answer:
(D) 200 and 2
Step-by-step explanation:
From the data given, the mean is 200
Standard error is obtained by dividing the population standard deviation by square root of the sample size.
population standard deviation = 18
sample size = 81
Standard error = population standard deviation ÷ sqrt (sample size) = 18 ÷ sqrt(81) = 18 ÷ 9 = 2
Mean = 200
Standard error = 2
