The length of rectangle is 48 yards and width of the rectangle is 8 yards, if the perimeter of the rectangle is 112 yards.
Step-by-step explanation:
The given is,
The perimeter of the rectangle is 112 yards
The length of a rectangle is six times it's width
Step:1
Let, p - Perimeter of the rectangle
l - Length of the rectangle
w - Width of the rectangle
Step:2
Formula for perimeter of rectangle,
[tex]Perimeter, p = 2(l+w)[/tex]............................(1)
From given,
p = 112 yards
l = 6w ( ∵ From given)
w = w
Substitute the values,
112 = 2 ( 6w + w )
112 = 2 ( 7w )
112 = 14w
w = 8 yards
From the w value, l becomes
l = 6w
l = 6 × 8
l = 48 yards
Result:
The length of rectangle is 48 yards and width of the rectangle is 8 yards, if the perimeter of the rectangle is 112 yards.
