Respuesta :
16.4 grams is the mass of solute in a 500 mL solution of 0.200 M .
sodium phosphate
Explanation:
Given data about sodium phosphate
atomic mass of Na3PO4 = 164 grams/mole
volume of the solution = 500 ml or 0.5 litres
molarity of sodium phosphate solution = 0.200 M
The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:
The formula is
molarity = [tex]\frac{number of moles of solute}{volume in litres}[/tex]
putting the values in the equation, we get
molarity x volume = number of moles
0.200 X 0.5= number of moles
number of moles = 0.1 moles
Atomic mass x number of moles = mass
putting the values in the above equation
164 x 0.1 = 16.4 grams
16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.
The mass of solute in 500mL solution is 16.4 grams. The number of moles can be calculated by using Molarity formula to find Mass of the solute.
Given:
Atomic mass of Na3PO4 = 164 grams/mole
Volume of the solution = 500 ml or 0.5 litres
Molarity of sodium phosphate solution = 0.200 M
Calculation of Molarity:
The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:
Molarity = Number of solute / Volume of solution
Molarity * volume = number of moles
0.200 * 0.5= number of moles
Number of moles = 0.1 moles
Mass= Atomic mass * number of moles
On subsituting:
164 * 0.1 = 16.4 grams
16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.
Find more information about Molarity here:
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