Answer:
0.2M
Explanation:
The molarity of a solution is given by;
M = number of moles / volume
Number of moles = mass/molar mass
Mass of Citric acid = 141.6g
Molar mass of citric acid = (6×12)+(8×1)+(7×16)
= 72+8+112=192g/mol
Number of moles of citric acid=141.6/192=0.74mol
Volume = 3500.0 mL = (3500/1000)L=3.5L
Molarity of the solution = 0.74mol/3.5L=0.2mol/L
Therefore, 0.2mol/L or 0.2M concentration is prepared by dissolving 141.6 g of citric acid, C3H5O(COOH)3, in 3500.0 mL of water
