Answer:
6/25
Step-by-step explanation:
Given two events A and B, the conditional probability of event A is the probability that event A occurs given that event B has occurred. It is calculated as
[tex]p(A|B)=\frac{p(A\cap B)}{p(B)}[/tex]
where
[tex]p(A\cap B)[/tex] is the probability that both A and B occur at the same time
[tex]p(B)[/tex] is the probability that B occurs
In this problem, we call:
A = the camera has a lens defect
B = the camera has a charging defect
Here we have:
a = 20 is the number of cameras with lens defects
b = 25 is the number of cameras with charging defects
c = 6 is the number of cameras having both defects
n = 800 is the total number of cameras
So we have:
[tex]p(A\cap B)=\frac{c}{n}=\frac{6}{800}[/tex] is the probability that the camera has both lens and charging defect
[tex]p(B)=\frac{b}{n}=\frac{25}{800}[/tex] is the probability that the camera has a charging defect
So the conditional probability is
[tex]p(A|B)=\frac{6/100}{25/100}=\frac{6}{25}[/tex]
