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ON THE SMARTBOARD, THE
MATH TEACHER DREW A
RECTANGLE WITH A PERIMETER
The
OF 406 cm. THE LENGTH OF THE
RECTANGLE IS 7cm LONGER
THAN THE WIDTH. FIND THE
DIMENSIONS OF THE RECTANGLE.

Respuesta :

The length of rectangle is 105 cm and width is 98 cm.

Step-by-step explanation:

Given,

Perimeter of rectangle = 406 cm

Let,

w be the width of rectangle

Length of rectangle = w+7

We know that

Perimeter of rectangle = 2(Length + Width)

[tex]406 = 2(w+7+w)\\406 = 2(2w+7)\\406 = 4w+14\\406-14 = 4w\\392=4w\\4w=392[/tex]

Dividing both sides by 4

[tex]\frac{4w}{4}=\frac{392}{4}\\w=98[/tex]

Width of rectangle = 98 cm

Length of rectangle = 98+7 = 105 cm

The length of rectangle is 105 cm and width is 98 cm.