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It is determined that a certain light wave has a wavelength of 3.012 ×10−12 m. The light travels at 2.99 ×108 m/s. What is the frequency of the light wave? (Round your answer to three significant figures.)

Respuesta :

Answer:

[tex]f=9.9269\,\,10^{19} Hz[/tex]

Explanation:

Recall that the velocity (v) of a light wave is defined as the product of its frequency (f)  times its wavelength ([tex]\lambda[/tex]) :

[tex]v=f*\lambda[/tex]

therefore, we can solve for the unknown frequency by dividing both sides of the equation by the frequency:

[tex]v=f*\lambda\\2.99\,\,10^{8} \frac{m}{s} = f *\,3.012\,\,10^{-12}\, m\\\frac{2.99\,\,10^8}{3.012\,\,10^{-12}} \frac{1}{s}=f\\ f=0.99269\,\,10^{20}\,\, \frac{1}{s}\\[/tex]

Since the units "1/second" are what we call Hertz (Hz), the answer can also be given as:

[tex]f=9.9269\,\,10^{19} Hz\,[/tex]

Answer:

f=9.93 × 1019 Hz

Explanation:

 

Use the relationship  f=vλ  to solve for frequency f. Substituting the known quantities yields:

 

f=vλf=2.99 × 108  m/s3.012 × 10-12 mf=9.926×1019  

 

answer rounded off to 3 significant digits is

 

f=9.93 × 1019 Hz