Answer:
[tex]c = 1[/tex]
Step-by-step explanation:
The given expresion is
[tex]2 {x}^{2} + 3x + c[/tex]
For this expression to be factorable using integers, we must find factors of 2c, that will sum up to 3.
We know 2,c are factors of 2c
Their sum should be 3.
[tex]c + 2 = 3[/tex]
This implies that:
[tex]c = 3 - 2 \\ c = 1[/tex]