contestada

What is the temperature of 4.75 moles of a substance at a pressure of 1.2 atm and a volume of 0.125 L? Use 0.0821 for R and significant digits (2 in this case). Report your answer in Kelvin.

Respuesta :

Neetoo

Answer:

T = 0.38 K

Explanation:

Given data:

Number of moles = 4.75 mol

Pressure = 1.2 atm

Volume = 0.125 L

R = 0.0821 atm.L /mol.K

Temperature = ?

Solution:

Formula:

PV = nRT

T = PV/nR

T = 1.2 atm × 0.125 L /  4.75 mol × 0.0821 atm.L /mol.K

T = 0.15  / 0.39 /K

T = 0.38 K

Otras preguntas