Answer:
The balanced equation is given below:
CH4 + 2O2 —> CO2 + 2H2O
The coefficients are: 1, 2, 1, 2
Explanation:
The equation for the Combustion of methane (CH4) is given below:
CH4 + O2 —> CO2 + H2O
Now we can balance the equation above as follow:
There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:
CH4 + O2 —> CO2 + 2H2O
Now, there are a total of 4 atoms of O on the right side and 2 atoms on the left. It can be balance by putting 2 in front of O2 as shown below:
CH4 + 2O2 —> CO2 + 2H2O
Now the equation is balanced.
The coefficients are: 1, 2, 1, 2
Answer:
The coefficients for CH4; O2; CO2; H2O are 1; 2; 1; 2
Explanation:
Step 1: Data given
The reactants are : CH4 and 02
The products are CO2 and H2O
Step 2: The unbalanced equation
CH4 + O2 → CO2 + H2O
Step 3: Balancing the equation
CH4 + O2 → CO2 + H2O
On the left side we have 4x H (in CH4) on the right side we have 2x H in (H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side by 2.
CH4 + O2 → CO2 + 2H2O
On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in H2O). To multiply the amount of O on both side we have to multiply O2 on the left side by 2. Now the equation is balanced.
CH4 + 2O2 → CO2 + 2H2O
The coefficients for CH4; O2; CO2; H2O are 1; 2; 1; 2
