A person invests 9000 dollars in a bank. The bank pays 4.25% interest compounded daily. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 19600?

Respuesta :

The person must invest the money in the bank for 18 years to reach $19600, if a person invests 9000 dollars in a bank and the bank pays 4.25% interest compounded daily.

Step-by-step explanation:

The given is,

                       A person invests 9000 dollars in a bank      

                      The bank pays 4.25% interest compounded daily

                      Future amount $19600

Step:1

                     Formula to calculate the future investment with compounded daily,

                                                  [tex]A = P (1+\frac{r}{n})^{nt}[/tex]................................(1)

                   Where, A - Future amount

                                P - Initial investment

                                r - Interested rate

                                n - No.of times for a year

                                t - No.of years

Step:2

              From the given values,

                      A = $ 19600

                      P = $ 9000

                       r = 4.25 %

                      n = 365  ( ∵ Compounded daily )

           Equation (1) becomes,

                                        [tex]19600 = 9000(1+\frac{0.0425}{365})^{365t}[/tex]

                                         [tex]\frac{19600}{9000}= (1+0.000116438)^{365t}[/tex]

                                   [tex]2.177778=(1.000116438)^{365t}[/tex]

            ( Take log on both sides )

                               [tex]log 2.17778= log (1.000116438)^{365t}[/tex]

                               [tex]log 2.17778=( 365t)log (1.000116438)[/tex]

           Substitute the log values,

                                  [tex]0.338014 = (365t)(0.000050565)[/tex]

                                [tex]\frac{0.338014}{0.000050565}= 365t[/tex]

                                [tex]6684.6842 = 365t[/tex]

                                              [tex]t = \frac{6684.6842}{365}[/tex]

                                                 = 18.314

                                                 ≅ 18 years

                          No.of years, t = 18 years

Result:

              The person must invest the money in the bank for 18 years to reach $19600, if a person invests 9000 dollars in a bank and the bank pays 4.25% interest compounded daily.

It will take approximately 18.4years for the person to make 19600

The formula for calculating the compound amount is expressed as:

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex] where:

A is the amount

P is the amount invested

n is the compounding amount

t is the time taken

Given the following parameters

A =  19600

P = 9000

r = 4.25% = 0.0425

n = 365 (compounded daily)

Substitute the given parameters into the formula to get the time "t"

[tex]19600 = 9000(1+\frac{0.0425}{365} )^{365t}\\2.1778 = (1+0.0001164)^{365t}\\2.1778 = (1.0001164)^{365t}\\log2.1778 = 365tlog(1.0001164)\\0.3380 = 0.0184t\\t = \frac{0.3380}{0.0184} \\t \approx 18yrs[/tex]

Hence it will take approximately 18.4years for the person to make 19600

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