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As an approximation, we can assume that proteins exist either in the native (or physiologically functioning) state or the denatured state. The standard molar enthalpy and entropy of the denaturation of a certain protein are 545 kJ·mol−1 and 1.55 kJ·K−1·mol−1, respectively. Comment on the signs and magnitudes of these quantities.

Respuesta :

Answer:

Reaction is spontaneous at high temperature and nonspontaneous at low temperature

Explanation:

Given:

Enthalpy change [tex]\Delta H= 545 \frac{KJ}{mol}[/tex]

Entropy change [tex]\Delta S = 1.55[/tex] [tex]\frac{KJ }{K. mol}[/tex]

From the formula of change in free energy,

  [tex]\Delta G = \Delta H - T\Delta S[/tex]

But for spontaneous process the values of quantities are given below

For spontaneous process value of [tex]\Delta G[/tex] is negative

For nonspontaneous process value of [tex]\Delta G[/tex] is positive

Here values of [tex]\Delta H[/tex] and [tex]\Delta S[/tex] are positive, so reaction is spontaneous at

high temperature and nonspontaneous at low temperature

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