Respuesta :
Answer:
4.988kW
Explanation:
According to the question, energy E extracted from the ocean breaker is directly proportional to the intensity I. It can be expressed mathematically as E ∝ I
E = kI where k is the constant of proportionality.
From the formula; k = E/I
This shows that increase in energy extracted will lead to increase in its intensity and vice versa.
If the device produces 10.0 kW of power on a day when the breakers are 1.20 m high
E = 10kW and I = 1.20m
k = 10/1.20
k = 8.33kW/m
To know how much energy E that will be produced when they are 0.600 m high, we will use the same formula
k = E/I where;
k = 8.33kW/m
I = 0.600m
E = kI
E = 8.33 × 0.6
E = 4.998kW
The device will produce energy of 4.998kW when they are 0.600m high.
Answer:
It will produce 2.5 Kw at 0.6m high
Explanation:
We are given;
Initial Power output of device; P_i = 10 Kw
Initial amplitude; A_i = 1.2m
Final Amplitude; A_f = 0.6m
We know that power is directly proportional to energy because
P = Energy(work done)/time taken
Thus; P ∝ E - - - - (eq1)
Now,from the question, we are told that Energy is proportional to the intensity. Thus;
E ∝ I - - - - (eq2)
where I is intensity
Now, from formula of Intensity, which is; I = (1/2)(ρ²•β²•ω²•A²)
We can see that I is directly proportional to square of Amplitude A²
Thus, I ∝ A² - - - - (eq3)
Combining eq 1,2 and 3,we can deduce that;
P ∝ E ∝ I ∝ A²
Thus, P ∝ A²
Now, let's set up the proportion as;
P_i/P_f = A_i²/A_f²
Since we are looking for final power, let us make P_f the subject.
So,
P_f = (P_i•A_f²)/A_i²
Plugging in the relevant values to obtain ;
P_f = (10 x 0.6²)/1.2² = 2.5 Kw
