Which polynomial has zeros of 2, 5, and -4?

A. (x + 2)(x + 5)(x - 4)
B. (2x - 4)(x + 5)(x + 4)
c. 6 - 2)(x - 5)(x - 4)
D. (2x - 4)(x - 5)(x + 4)

Respuesta :

Answer:

Step-by-step explanation:

(a) p(2)=(2+2) (2+5) (2-4)

=4*7*-2

=-56

So this is not the polynomial

(b) p(2)=(4-4) (2+5) (2+5)

=0*7*7

0

p(5)=(10-4)(5+5)(5+4)

6*10*9

=540

So this is also not the polynomial

(c)p(2)=(6-2)(2-5)(2-4)

4*-3*-2

24

so this is also not the polynomial

(d)p(2)=(4-4)(2-3)(2+4)

=0

p(5)=(10-4)(5-5)(5+4)

=0

p(-4)=(-8-4)(-4-5)(-4+4)

=0

so this is the polynomial

The polynomial has zeros of 2, 5, and -4 is option (d) (2x - 4)(x - 5)(x + 4).

What is polynomial?

A polynomial is a mathematical equation made up of indeterminates and coefficients and uses only addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

How to find the correct polynomial?

To find a polynomial that has zeros 2, 5, and -4 substituted x = 2, 5, and -4 in a polynomial.

By substituted x = 2, 5, and -4 in a polynomial (2x - 4)(x - 5)(x + 4).

(a) For x=2.

The polynomial is

(2(2) - 4)(2- 5)(2 + 4) = (4- 4)(-3)(6)

                                 = 0×-3×6

                                 = 0

(b) For x=5.

The polynomial is

(2(5) - 4)(5 - 5)(5 + 4) = (10-4)(0)(9)

                                  = 6×0×9

                                  = 0

(c) For x=-4.

The polynomial is

(2(-4) - 4)(-4 - 5)(-4 + 4) = (-8-4)(-9)(0)

                                  = -`12×-9×0

                                  = 0

Since (2x - 4)(x + 5)(x + 4) has zeros of 2, 5, and -4

For incorrect options

By substituted x = 2, 5, and -4 in a polynomial  (x + 2)(x + 5)(x - 4), (2x - 4)(x + 5)(x + 4) and (6x - 2)(x - 5)(x - 4) is not equal to zero therefore (a), (b) and (c)is not correct option.

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