Answer:
Tension in the string is equal to 58.33 N ( this will be the strength of the string )
Explanation:
We have given mass m = 1.7 kg
radius of the circle r = 0.48 m[tex]F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N[/tex]
Kinetic energy is given 14 J
Kinetic energy is equal to [tex]KE=\frac{1}{2}mv^2[/tex]
So [tex]\frac{1}{2}\times 1.7\times v^2=14[/tex]
[tex]v^2=16.47[/tex]
v = 4.05 m/sec
Centripetal force is equal to [tex]F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N[/tex]
So tension in the string will be equal to 58.33 N ( this will be the strength of the string )
