Which of the following compounds would be consistent with a compound showing an M with an m/z ratio of 43 in a mass spectrometer? Select all that apply.
a. CH3CH2OH
b. CH3CH2NH2
c. propane
d. propene
e. None of the choices are correct.

Respuesta :

Answer:

The option (e) None of the choice are correct.

Explanation:

To find [tex]\frac{m}{z}[/tex] ratio in mass spectrometer,

We start calculating from the first option

(a)

 [tex]CH_{3}- CH_{2}- OH[/tex]

We know mass of carbon [tex]m= 12[/tex] and atomic number of carbon [tex]Z = 6[/tex]

After calculating we come up with,

[tex]\frac{m}{z} = 46[/tex]

Therefore option (a) is incorrect.

(b)

  [tex]CH_{3} -CH_{2}- NH_{2}[/tex]

After calculating we come up with,

[tex]\frac{m}{z} = 45[/tex]

Therefore option (b) is incorrect.

(c)

  [tex]CH_{3}- CH_{2}-CH_{3}[/tex]

[tex]\frac{m}{z} = 44[/tex]

Therefore option (c) is incorrect.

(d)

  [tex]CH_{3}- CH=CH_{2}[/tex]

[tex]\frac{m}{z} = 42[/tex]

Therefore option (d) is incorrect.

Therefore, the option (e) is correct for this problem