Respuesta :
Answer:
Check the explanation
Explanation:
A. Calcite ------> Argonite
At 298 K and 1 atm,
\DeltaGrxn = \DeltaGarg - \DeltaGcalc
= -1127.71-(-1128.76) = 1.05 kJ/mol
\DeltaGrxn is positive, so the reaction is not spontaneous.
Thus, the reaction would not happen even if enough time is given.
B. Molar mass of CaCO3 = 100 g/mol
Volume = mass/density
Vcalc = 100/2.710 = 36.900 ml/mol = 36.9*10-3 L = 36.9*10-6 m3
Varg = 100/2.930 = 34.130 ml/mol = 34.13*10-3 L = 34.13*10-6 m3
\DeltaGrxn = 1.05 kJ/mol = 1.05*103 J/mol
\DeltaG = -\DeltaP\DeltaV
\DeltaP = -\DeltaG/\DeltaV = -1.05*103/(34.13*10-6 - 36.9*10-6) = 0.379*109 Pa = 3.79*108 Pa
The pressure should be more than 3.79*108 Pa.
C. For reaction, \DeltaSrxn = Sarg - Scalc
= 88.70-92.88 = -4.18 J/mol.K
\DeltaHrxn = -1207.04-(-1206.87) = -0.17kJ/mol
At 400 K, \DeltaG = \DeltaH-T\DeltaS
= -0.17-(400*-4.18)
= +ve
So, the reaction is not favorable on increasing the temperature to 400 K.
D. \DeltaT = 400-298 = 102 K
\DeltaP = 1000-1 = 999.0 atm = 999*106 Pa
\DeltaG = \DeltaS\DeltaT - \DeltaV\DeltaP
= (-4.18*102)-(-2.77*10-6*999*106)
= -426.36+2767.23 = 2340.87 J/mol
\DeltaG = +ve
calcite would be more stable.