Answer:
The speed off the wheel at the top is 4.57 m/s.
Explanation:
Given that,
A Ferris wheel on a California pier is 38 m high and rotates once every 26 seconds in the counterclockwise direction. 38 m will be the diameter of the wheel. The angular speed of the wheel is given by :
[tex]\omega=\dfrac{2\pi}{T}\\\\\omega=\dfrac{2\pi}{26}\\\\\omega=0.241\ rad/s[/tex]
We need to find the speed of the wheel when you are at the very top. So,
[tex]v=r\omega\\\\v=19\times 0.241\\\\v=4.57\ m/s[/tex]
So, the speed off the wheel at the top is 4.57 m/s.
