Respuesta :

Explanation:

Hello! Remember you have to write clear questions in order to get good and exact answers. Here, I'll assume the function as:

[tex]f(x)=x^2+2x-16[/tex]

The y-intercept of a function is the point at which the graph of the function touches the y-axis. This occurs when we set [tex]x=0[/tex]. In other words, we define the y-intercept (let's call it [tex]b[/tex] as:

[tex]b=f(0)[/tex]

Setting [tex]x=0[/tex] in our function we have:

[tex]b=f(0)=(0)^2+2(0)-16 \\ \\ \boxed{b=f(0)=-16}[/tex]

So in this context the y-intercept is -16

Answer:

-16

Step-by-step explanation:

got it right on edge