Increasing the volume in which a substance is dissolved, decreases the concentration
The correct option to when equal volumes of equimolar solution are combined, the concentration of each solution is the option;
a. Increases by one half
Reason:
The definition of molarity of a solution is the number of moles present in one liter of the solution
Equimolar solution are solutions that have equal number of moles in a given amount of solution
Let A and B, represent the number of moles of the substances in each solution, and let V, represent the volume of the of each solution, we have;
[tex]Molarity \ of \ A = \dfrac{A}{V}[/tex]
[tex]Molarity \ of \ B = \dfrac{B}{V}[/tex]
The volume of the the two solutions combined = V + V = 2·V
In the situation where there is no reaction between the contents of the two solutions, we have that the concentration of A, in the combined volume are;
[tex]Molarity \ of \ A \ in \ combined \ solution= \dfrac{A}{2 \cdot V} = \dfrac{1}{2} \times \dfrac{A}{V}[/tex]
[tex]Molarity \ of \ B \ in \ combined \ solution= \dfrac{B}{2 \cdot V} = \dfrac{1}{2} \times \dfrac{B}{V}[/tex]
Therefore, the concentration of A, and B is half of the initial concentration or the concentration decreases by half
Learn more about mixtures here:
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