Answer:
The energy needed to raise the temperature 18.0 grams of water is from 10.0°C to 40.0°C is 2,257.2 Joules.
Explanation:
[tex]Q=mc\Delta T=mc\times (T_2-T_1)[/tex]
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
[tex]T_1,T_2[/tex] : Initial and final temperature of the substance
We have mass of water = m = 18.0 g
Specific heat of water= c = 4.18 J/g°C
Initial and final temperature of the water= [tex]T_1=10.0^oC [/tex]
Final temperature of the water= [tex]T_2=40.0^oC[/tex]
Heat absorbed by the water:
[tex]Q=18.0g\times 4.18/g^oC\times (40.0^oC-10.0^oC)=2,257.2 J[/tex]
The energy needed to raise the temperature 18.0 grams of water is from 10.0°C to 40.0°C is 2,257.2 Joules.
