Answer: The volume the gas will occupy at STP is 6.9 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 750 torr = 0.99 atm (760torr=1atm)
[tex]P_2[/tex] = final pressure of gas = 1 atm (at STP)
[tex]V_1[/tex] = initial volume of gas = 8.2 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]48^oC=273+48=321K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]273K[/tex] (at STP)
Now put all the given values in the above equation, we get:
[tex]\frac{0.99\times 8.2}{321}=\frac{1\times V_2}{273}[/tex]
[tex]V_2=6.9[/tex]
Thus volume the gas will occupy at STP is 6.9 L
