A sheet of copper is 5 mm thick and has
surface dimensions of 7 cm × 22 cm .
If the long edges are joined to form a
tube 22 cm in length, what is the resistance between the ends? The mass density
of copper is 8920 kg/m3
and its resistivity is
1.7 × 10−8 Ω · m .
Answer in units of Ω

Respuesta :

Answer:

[tex]R=2.42\times 10^{-7}\ \Omega[/tex]

Explanation:

We have,

Dimension of the sheet is 7 cm × 22 cm.

Length of the tube, l = 22 cm

Resistivity of the copper wire is [tex]\rho=1.7\times 10^{-8}\ \Omega-m[/tex]

It is required to find the resistance between the ends. We know that the formula of resistance is given by :

[tex]R=\rho \dfrac{l}{A}[/tex]

A is area of sheet

[tex]R=1.7\times 10^{-8}\times \dfrac{0.22}{0.07\times 0.22}\\\\R=2.42\times 10^{-7}\ \Omega[/tex]

So, the resistance between the ends is [tex]2.42\times 10^{-7}\ \Omega[/tex].