Respuesta :
Answer:
(b)0.56
(c)0.38
Step-by-step explanation:
(a)The tree diagram is attached.
P(Ben Fails)=1-0.8=0.2
P(Tom Fails)=1-0.7=0.3
(b)Probability that both will pass their driving test.
P(both will pass)=0.8 X 0.7 =0.56
(c)Probability that only one of them will pass their driving test.
P(Tom Bass, Ben Fails OR Ben Pass, Tom Fails)
=(0.7 X 0.2)+(0.8 X 0.3)
=0.14+0.24
=0.38
Following are the solution to the given points:
- For point a please find the attached file.
- The likelihood of both passing their driving tests is [tex]\bold{p=0.8\times 0.7=0.56}[/tex] Since both they pass their driving test at the same time, so we multiply the chance of each one, yielding a result of "56%".
- Ben succeeds but Tom fails, or Ben fails but Tom pass. So, the probability is [tex]\bold{p=0.8 \times 0.3 +0.2 \times 0.7=0.24+0.14=0.38}[/tex] and the answer is "38%".
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