0.80 mol MgBr2 is added to 1.00 kg water. Determine the freezing point of the solution. Water has a freezing point depression constant of 1.86°C•kg/mol. Which equation should you use?

Respuesta :

Answer:B

2.4

-4.5

-4.5

Explanation:

The answer is option B. -4.5°C or 268.5 kelvin.

What is depression in freezing?

freezing point depression  =  1.86 ° C kg/mol.    

molality = 0.80 mol / 1.00 kg

 T= (K ) (molality)

 T = 1.86 * 0.86

  • Calculate the freezing point of benzene. T = (Freezing factor of pure solvent) - (Freezing point of the answer).
  • Calculate the molal concentration of the molality = moles of solute/kg of solvent. ...
  • Calculate the Kf of the answer. T = (K) (m)

The freezing point of water in kelvin is 273.15 k. The relation between Celsius and Kelvin scales of temperature is TKelvin = TCelsius + 273.15. The freezing point of water in Celsius is 0 °C; hence, the freezing point is 273.15 Kelvin scale.

Learn more about depression in freezing point here:-https://brainly.com/question/17048792

#SPJ2