Answer: 45.3mph
Step-by-step explanation:
There is a formula that relates the distance calculated by the product of speed and time.
[tex]d=v*t[/tex]
d = distance
v = speed
t = time
If we take a look at your problem, you have a distance of
[tex]d=30 \frac{1}{5}mi[/tex] = [tex]\frac{151}{5} mi[/tex]
and a time of;
[tex]t=\frac{2}{3}[/tex] of an hour
and you need to find the average speed (v)
[tex]v=?[/tex]
Solve for v;
[tex]v=\frac{d}{t}[/tex]
[tex]v=\frac{\frac{151}{5}mi }{\frac{2}{3}h }[/tex]
Multiply by the reciprocal of the fraction in the denominator. Or simply invert the denominator and multiply by the numerator.
[tex]v=\frac{151}{5}mi*\frac{3}{2}h[/tex]
[tex]v=45.3mph[/tex]
