Respuesta :
Answer:
You can decide to reject the Null Hypothesis at p < 0.05.
Step-by-step explanation:
In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.
The categories of childhood trauma are:
Trauma and No trauma.
So, number of rows is, r = 2.
The categories of weight in adulthood are:
Low to normal, Overweight, and Obese
So, number of columns is, c = 3.
The distribution of the statistic [tex]\chi^{2}[/tex] is chi-square with (r - 1)(c - 1) degrees of freedom, where r represents the number of rows in the two-way table and c represents the number of columns.
Compute the degrees of freedom as follows:
[tex]df = (r-1)(c-1)=(2-1) \times (3-1) = 2[/tex]
It is provided that the calculated value of Chi-square test statistic is 18.26.
Compute the p-value of the test as follows:
[tex]p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011[/tex]
Decision rule:
The null hypothesis will be rejected if the p-value of the test is less than the significance level.
The significance level is, α = 0.05.
p-value = 0.00011 < α = 0.05.
The null hypothesis will be rejected at 5% level of significance.
Thus, the complete statement is:
"You can decide to reject the Null Hypothesis at p < 0.05."