Answer:
The P-value is 0.009.
Step-by-step explanation:
We are given that after debating whether this set of hockey players can be viewed as a random sample of hockey players, they decide to run a hypothesis test anyway to practice finding the P‐value.
We are given that the following hypothesis below;
Null Hypothesis, [tex]H_0[/tex] : p = 0.25
Alternate Hypothesis, [tex]H_A[/tex] : p > 0.25
Now, the test statistics that was used here for the above hypothesis would be;
T.S. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
Also, the test statistics given to us is 2.37.
SO, the P-value of the test statistics is given by the following formula;
P-value = P(Z > 2.37) = 1 - P(Z [tex]\leq[/tex] 2.37)
= 1 - 0.99111 = 0.00889 ≈ 0.009
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.99111.
Therefore, the required P-value is 0.009.