Respuesta :

aabdulsamir

Answer:

Q = 8368J

Explanation:

Mass(m) = 40g

Initial temperature (T1) = 25°C

Final temperature (T2) = 75°C

Specific heat capacity (c) = 4.184J/g°C

Heat energy (Q) = ?

Q = Mc∇T

Q = Mc * (T2 -T1)

Q = 40 * 4.184 * (75 - 25)

Q = 167.36 * 50

Q = 8368J

The heat energy required to raise the temperature from 25°C to 75°C is 8368J

Ritmeks

The energy required is 8368 Joules

The calculation can be done as follows

Mass= 40 grams

t1= 25°c

t2= 75°c

capacity= 4.84 J/g

Q= MC (t2-t1)

Q= 40×4.184(75-25)

= 167.36(50)

= 8,368

Hence the energy required is 8368 Joules

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https://brainly.com/question/23628768?referrer=searchResults

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