Answer:
[tex]e^{-2x}=16[/tex]
Step-by-step explanation:
For logarithmic equations:
[tex]Log_{a}x=b $ is equivalent to a^b=x, x>0, a>0, a\neq -1[/tex]
In ln(16) = -2x
Ln is the natural logarithm, and:
a= e
x=16
b=-2x
Therefore, in exponential form, the equivalent form is:
[tex]e^{-2x}=16[/tex]
Answer:
The exponential form is: [tex]e^{-2x}[/tex] = 16
Step-by-step explanation:
In(16) = -2x
The natural logarithm (In) is the inverse of the exponential function,
i.e In [tex]e^{b}[/tex] = b
Thus, find the exponential function of both sides;
In(16) = -2x
e In(16) = e (-2x)
⇒ 16 = [tex]e^{-2x}[/tex]
i.e [tex]e^{-2x}[/tex] = 16
So that;
[tex]\frac{1}{e^{2x} }[/tex] = 16
