Given that the slope is rise over run, the slope of AB, BC and AC are the same as [tex]\mathbf{\frac{2}{3} }[/tex], therefore, the statement that is NOT true is: The slope of [tex]\overline{AB}[/tex] is different than the slope of [tex]\overline{BC}[/tex].
Recall:
- The slope along a line is calculated as: the rise/the run
From the given image attached below, we can find the slopes of AB, BC, and AC by finding the the rise over the run of each segment in the diagram attached below.
Slope of AB:
rise = 2
run = 3
Slope = [tex]\frac{2}{3}[/tex]
Slope of BC:
rise = 4
run = 6
Slope = [tex]\frac{4}{6}= \frac{2}{3}[/tex]
Slope of AC:
rise = 6
run = 9
Slope = [tex]\frac{6}{9} = \frac{2}{3}[/tex]
Thus, given that the slope is rise over run, the slope of AB, BC and AC are the same as [tex]\mathbf{\frac{2}{3} }[/tex], therefore, the statement that is NOT true is: The slope of [tex]\overline{AB}[/tex] is different than the slope of [tex]\overline{BC}[/tex].
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