A fossil is found that contains 10% of the amount of carbon-14 found in a living being. About how old is the fossil?

A. 15,300 years

B. 17,600 years

C. 19,200 years

D. 20,700 years

30 POINTS!

Respuesta :

Answer:

C. 19,200

Step-by-step explanation:

half of a life of c-14 is

5,730

this has gone over 3.3 lives

multiply 5,730 by 3.3

you get

about the answer C

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The age of the fossil using carbon dating comes out to be 19188.21 years.

What is the formula for carbon-14 dating?

The formula for carbon-14 dating is given by:

[tex]A = Ie^{kt}[/tex]

Where A = Amount

I =initial amount

k=constant of growth or decay

[tex]\frac{A}{I} =e^{kt}[/tex]

In the case of a half-life

[tex]0.5=e^{kt_{1/2} }[/tex]

[tex]ln 0.5 = k\frac{t_{1/2} }{2}[/tex]

We know the half-life of carbon-14 is 5700 years i.e. [tex]t_{1/2} =5700[/tex]

So, [tex]ln 0.5 = k\frac{5700}{2}[/tex]

[tex]k=-0.00024[/tex]

According to the question

[tex]ln0.1 = -0.00024*\frac{t}{2}[/tex]

[tex]2ln0.1 = -0.00024*t[/tex]

[tex]t = 19188.21[/tex] years.

Hence, The age of the fossil using carbon dating comes out to be 19188.21 years.

To get more about carbon dating visit:

https://brainly.com/question/15673495