Answer:
The values are [tex]x=2\sqrt{2}[/tex] and [tex]y=2\sqrt{6}[/tex].
Step-by-step explanation:
A right triangle is a type of triangle that has one angle that measures 90°.
In a right triangle, the sine of an angle is the length of the opposite side divided by the length of the hypotenuse.
[tex]\sin(\theta)=\frac{opposite \:site}{hypotenuse}[/tex]
To find the value of x we use the above definition. From the diagram we can see that the angle is 30º and the hypotenuse is [tex]4\sqrt{2}[/tex]. Therefore,
[tex]\sin(30)=\frac{x}{4\sqrt{2} }\\\\\frac{x}{4\sqrt{2}}=\sin \left(30^{\circ \:}\right)\\\\\frac{8x}{4\sqrt{2}}=8\sin \left(30^{\circ \:}\right)\\\\\sqrt{2}x=4\\\\\frac{\sqrt{2}x}{\sqrt{2}}=\frac{4}{\sqrt{2}}\\\\x=2\sqrt{2}[/tex]
To find the value of y we use the above definition. From the diagram we can see that the angle is 60º and the hypotenuse is [tex]4\sqrt{2}[/tex]. Therefore,
[tex]\sin(60)=\frac{y}{4\sqrt{2} }\\\\\frac{y}{4\sqrt{2}}=\sin \left(60^{\circ \:}\right)\\\\\frac{8y}{4\sqrt{2}}=8\sin \left(60^{\circ \:}\right)\\\\\sqrt{2}y=4\sqrt{3}\\\\\frac{\sqrt{2}y}{\sqrt{2}}=\frac{4\sqrt{3}}{\sqrt{2}}\\\\y=2\sqrt{6}[/tex]
