Answer:
12a. (-6, -6)
12b. 17
13a. y = [tex]\frac{-1}{2}[/tex] x + [tex]\frac{3}{2}[/tex]
13b. 2
Step-by-step explanation:
12a. Using the midpoint formula:
[tex](\frac{-9-3}{2} ,\frac{2-14}{2} )[/tex] = [tex](\frac{-12}{2} , \frac{-12}{2})[/tex] = (-6, -6)
12b. Using the Distance formula:
d = [tex]\sqrt{(3 - (-9))^{2} +( 14 - 2)^{2} }[/tex] = [tex]\sqrt{(12)^{2}+(12)^{2} }[/tex] = [tex]\sqrt{144 + 144}[/tex] = [tex]\sqrt{288}[/tex]
= 12[tex]\sqrt{2}[/tex] or 17
13a. x + 2y = 3
2y = 3 - x
y = [tex]\frac{-1}{2}[/tex] x + [tex]\frac{3}{2}[/tex]
13b. The perpendicular slope is 2
