In quadrilateral BCED, we have BD = 11, BC = 9, and CE=2. Sides BD and CE are extended past B and C, respectively, to meet at point A. If AC = 28 and AB = 24, then what is DE?

Respuesta :

Answer:

DE = 11.25 units

Step-by-step explanation:

The image of the quadilateral BCED and the extensions of BD and CE to move past B and C to meet at A is presented in the attached file to this answer.

Let the angle at A be θ

Let the length of DE be x

ABC forms a triangle which van allow θ to be obtained using cosine rule.

BC² = AB² + AC² - (2×AB×AC×cos θ)

BC = 9

AB = 24

AC = 28

9² = 24² + 28² - (2×24×28×cos θ)

-1279 = -1344 cos θ

Cos θ = (1279/1344) = 0.9516

θ = 17.89°

Note that ADE also forms a triangle and we can also use cosine rule to obtain the required side DE

DE² = AD² + AE² - (2×AD×AE×cos θ)

DE = ?

AD = AB + BD = 24 + 11 = 35

AE = AC + CE = 28 + 2 = 30

θ = 17.89°

DE² = 35² + 30² - (2×35×30×cos 17.89°)

DE² = 126.54

DE = √126.54 = 11.25

Hope this Helps!!!

Ver imagen AyBaba7

The value of DE in the quadrilateral is 11.25 units.

How to solve the quadrilateral?

From the information given, the cosine rule can be used. This will be:

BC² = AB² + AC² - (2 × AB ×AC × cos)

Therefore,

9² = 24² + 28² - (2 × 24 × 28 × cos)

cos = 17.89°

Therefore, the value of DE will be calculated thus:

DE² = 35² + 30² - (2 × 35 × 30 × cos 17.89)

DE = ✓126.54

DE = 11.25

In conclusion, the value of DE is 11.25 units.

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