Answer:
[tex]x = 6.6[/tex] and [tex]DE = 16.2[/tex]
Step-by-step explanation:
The question is incomplete as the attachment to solve segment DE is missing. However, see attached for complete question.
Given
[tex]\frac{5}{9}= \frac{9}{(2x+3)}[/tex]
Required
Find x
Length of DE
To find x, we need to first simplify the given equation
[tex]\frac{5}{9}= \frac{9}{(2x+3)}[/tex]
Multiply both sides by [tex]9(2x+3)[/tex]
[tex]\frac{5}{9} * 9(2x + 3) = \frac{9}{(2x+3)} * 9(2x + 3)[/tex]
[tex]5(2x + 3) = 9(9)[/tex]
[tex]10x + 15 = 81[/tex]
Subtract 15 from both sides
[tex]10x + 15 - 15 = 81 - 15[/tex]
[tex]10x = 66[/tex]
Divide both sides by 10
[tex]\frac{10x}{10} = \frac{66}{10}[/tex]
[tex]x = \frac{66}{10}[/tex]
[tex]x = 6.6[/tex]
From the attached;
[tex]DE = 2x + 3[/tex]
Substitute 6.6 for x
[tex]DE = 2(6.6) + 3[/tex]
[tex]DE = 13.2 + 3[/tex]
[tex]DE = 16.2[/tex]
Hence [tex]x = 6.6[/tex] and [tex]DE = 16.2[/tex]
Answer: 6.6 for the first x
Length of DE is 16.2
Also these are correct!
Step-by-step explanation:
I just put it in
