Answer:
The time interval is [tex]t = 6.667 \ s[/tex]
Explanation:
From the question we are told that
The acceleration of the car is [tex]a = 3 m/s^2[/tex]
The velocity of the car is [tex]v= 20.0 \ m/s[/tex]
The final velocity of the car can be mathematically represented as
[tex]v =u + at[/tex]
Now since the car start from rest u = 0 So
[tex]v = 0 + at[/tex]
[tex]v = at[/tex]
substituting values
[tex]20 = 3 t[/tex]
[tex]t = \frac{20}{3}[/tex]
[tex]t = 6.667 \ s[/tex]
