Answer:
1296 [tex]m^{3}[/tex] of water
Explanation:
Area of landfill is 6000 [tex]m^{2}[/tex]
Rain fall depth is 300 mm = 300 x [tex]10^{-3}[/tex] m
volume of water that fall on the landfill is area x depth of water
v = 6000 x 300 x [tex]10^{-3}[/tex] = 1800 [tex]m^{3}[/tex] of water
20% of this precipitate is runoff i.e 0.2 x 1800 = 360 [tex]m^{3}[/tex]
total volume that infiltrates is 1800 - 360 = 1440 [tex]m^{3}[/tex]
the leachate treatment is 90% effective in treating infiltrates, i.e 90% of 1440 [tex]m^{3}[/tex] = 0.9 x 1440 = 1296 [tex]m^{3}[/tex] of water water is treated yearly
An area where waste material and garbage's are buried in the soil layers and covered with soil for disposing of wastes is called a landfill.
The 1296 [tex]\rm m^{3}[/tex] of volume is required for treating the landfill.
The volume can be estimated as:
Given,
Then,
Volume (v) of water that falls on the landfill:
v = Area x depth of water
[tex]\begin{aligned}\rm v & = 6000 \times 300 \\\\&= 1800 \;\rm m^{3}\end{aligned}[/tex]
20% of this precipitate is runoff:
[tex]\begin{aligned} &= 0.2 \times 1800 \\\\&= 360\end{aligned}[/tex]
Total volume = V
[tex]\begin{aligned}\rm V &= 1800 - 360 \\\\&= 1440 \;\rm m^{3}\end{aligned}[/tex]
Effective amount of treatment = 90% of 1440 [tex]\rm m^{3}[/tex]
[tex]\begin{aligned}&= 0.9 \times 1440 \\&= 1296 \;\rm m^{3} \end{aligned}[/tex]
Therefore, 1296 [tex]\rm m^{3}[/tex] is the volume.
To learn more about landfills follow the link:
https://brainly.com/question/3249873
