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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the systems of equations with their solution sets. y + 12 = x2 + x x + y = 3 y − 15 = x2 + 4x x − y = 1 y + 5 = x2 − 3x 2x + y = 1 y − 6 = x2 − 3x x + 2y = 2 y − 17 = x2 − 9x -x + y = 1 y − 15 = -x2 + 4x x + y = 1 Solution Set Linear-Quadratic System of Equations {(-2, 3), (7, -6)} arrowRight {(-5, 8), (3, 0)} arrowRight {(-2, 5), (3, -5)} arrowRight {(2, 3), (8, 9)} arrowRight

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ajeigbeibraheem

Answer:

Step-by-step explanation:

The solution of this systems of equations is the intersection of both graphs

Let's kick start with a:

a)

[tex]y+12 = x^2+x \\ \\ x+3 = y[/tex]

From the first attached diagram by using graph:

the solution is the set {(-5, 8), (3, 0)}

b)

[tex]y-15=x^3+4x \\ \\ x-y =1[/tex]

Using the graph tool from the last diagram below;

the solution is the set⇒( there is no solution)

c)

[tex]y+5 =x^2-3x \\ \\ 2x+y =1[/tex]

From the second attached diagram by using graph:

the solution is the set {(-2, 5), (3, -5)}

d)

[tex]y-6=x^2-3x \\ \\ x+2y =2[/tex]

the solution is the set ⇒ there is no solution (shown in the last diagram  below)

e)

[tex]y-17=x^2-9x \\ \\ -x+y =1[/tex]

the solution is the set {(2, 3), (8, 9)} as shown in the third diagram

f) Lastly:

[tex]y-15=-x^2+4x \\ \\ x+y =1[/tex]

Using the graph tool from the fourth diagram below;

the solution is the set  {(-2, 3), (7, -6)}

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MrRoyal

The solution to the system of equations are the truth values of the system of equations

[tex]\mathbf{(a)\ y + 12 = x^2 + x,\ x + 3 = y}[/tex]

The graphs of the equations intersect at (-5,8) and (3,0).

So, the solution set is {(-5,8), (3,0)}

[tex]\mathbf{(b)\ y - 15 = x^3 + 4x,\ x - y = 1}[/tex]

The graphs of the equations do not intersect

So, the system has no solution

[tex]\mathbf{(c)\ y + 5 = x^2 - 3x,\ 2x + y = 1}[/tex]

The graphs of the equations intersect at (-2,5) and (3, -5).

So, the solution set is {(-2, 5), (3, -5)}

[tex]\mathbf{(d)\ y - 6 = x^2 - 3x,\ x + 2y = 2}[/tex]

The graphs of the equations do not intersect

So, the system has no solution

[tex]\mathbf{(e)\ y - 17 = x^2 - 9x,\ -x + y = 1}[/tex]

The graphs of the equations intersect at (2,3) and (8,9).

So, the solution set is {(2, 3), (8, 9)}

[tex]\mathbf{(f)\ y - 15 = -x^2 + 4x,\ x + y = 1}[/tex]

The graphs of the equations intersect at (-2,3) and (7,-6).

So, the solution set is {(-2, 3), (7, -6)}

Read more about system of equations at:

https://brainly.com/question/12895249

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