Respuesta :
Answer: H = 30ft*cos(2*pi*t/48s + pi) + 38ft.
Step-by-step explanation:
We can use a trigonometric function to model this, let's use:
H = A*cos(w*t) +
where A is a constant, w is the frequency, t is time, and h is of the wheel, this is half the diameter plus the distance above the ground:
30ft + 8ft = 38ft.
A is equal to the radius of the wheel, or half the diameter, A = 60ft/2 = 30ft.
we know that the period is 48 seconds, this means that:
cos(w*0) = cos(w*48s) = 1
then w*48s = 2*pi
w = 2*pi/48s
so now function is:
H = 30ft*cos(2*pi*t/48s) + 38ft.
But we also know that, at t= 0, you must be at the bottom of the wheel, so we must ad a phase of pi to the cosine function
H = 30ft*cos(2*pi*t/48s + pi) + 38ft.
So now when t = 0, we have:
H(0) = 30ft*cos(0 + pi) + 38ft. = 8ft.
[tex]\rm H = 30cos \frac{2 \pi t}{48} + 38 \ ft.[/tex] is the obtained equation below model your height above the ground as a function of time.
What is the equation?
A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
Given data;
A is a constant,
ω is the frequency
t is the passage of time
h is the wheel's height,
d is the diameter
h = d/2
The equation for the SHM is found as;
y = Acosωt
For the given condition the equation is written as;
H = Acosωt
The distance above the ground;
30ft + 8ft = 38ft.
⇒cos(ωt)
⇒cos(w × 48) = 1
⇒ω×48s = 2π
⇒w = 2π/48s
The obtained function is;
[tex]\rm H = 30cos \frac{2 \pi t}{48} + 38 \ ft.[/tex]
We must add a phase of π to the cosine function since we also know that at time t=0, you must be at the bottom of the wheel.
So now when t = 0, we have:
[tex]\rm H(0) = 30ft\times cos(0 + \pi) + 38ft.\\\\\ H(0) = 8 \ ft.[/tex]
To learn more, about equations, refer;
https://brainly.com/question/10413253
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