Respuesta :
Answer:
[tex]\dfrac{9}{19}[/tex]
Step-by-step explanation:
It is given that there are a total of 19 cards ({1,2,3,4, ...... ,19}).
Let S be the set of total cards.
S ={1,2,3,4, ...... ,19}
Total number of observations, n(S) = 19
Even number of cards is the set {2,4,6,8,10,12,14,16,18}
Total number of cards with even number on it = 9
Let E be the event of selecting a card with even number on it.
n(E) = 9
Probability of an event A can be formulated as:
[tex]P(A) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}[/tex]
In this case, formula of P(E) is:
[tex]P(E) = \dfrac{n(E)}{n(S)}[/tex]
[tex]\Rightarrow \dfrac{9}{19}[/tex]
The probability that the card chosen at random is an even number is:
[tex]\dfrac{9}{19}[/tex]
The probability that the card will have an even number will be 0.4737.
- From the information given, we are informed that a bag contains 19 cards numbered 1 through 19.
- Based on the information, the even numbers will be 2, 4, 6, 8, 10, 12, 14, 16, and 18. Therefore, the probability of having when numbers will be:
= 9/19 = 0.4737
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