Respuesta :
Answer
160ft
Step-by-step explanation:
Let the width be x.
Then the length is (x+200)
The area of the field=57600
Area=length*width
x(x+200)=57600
x^2+200x-57600=0
x=-360 or x=160
The width and length of the football field are 160 feet and 360 feet respectively.
Suppose the width of the field = x
So, the length of the field =x+200
What is the area of a rectangle?
The area of a rectangle with length l and width b is lb.
So, the area of the football field =x(x+200)
Given that x(x+200)=57600
[tex]x^{2} +200x=57600[/tex]
[tex]x^{2} +200x-57600=0[/tex]
[tex]x=\frac{-200+\sqrt{200^2-4*1*(-57600)} }{2}[/tex]
x=160
So, the width of the field is 160 feet.
Hence, the width and length of the football field are 160 feet and 360 feet respectively.
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