PLEASE HELP?



Suppose the sphere below with radius r has a surface area equal to 50 units². find the surface area of the sphere with twice the radius.

Respuesta :

Answer:

[tex]200$ unit^2[/tex]

Step-by-step explanation:

Surface Area of a Sphere[tex]=4\pi r^2[/tex]

Given that the surface area of a sphere is 50 units².

Then:

[tex]4\pi r^2 =50\\r^2=\dfrac{50}{4\pi}\\ r=\sqrt{\dfrac{50}{4\pi}}[/tex]

If a sphere has twice the radius of the sphere above

Its radius, [tex]r=2\sqrt{\dfrac{50}{4\pi}}[/tex]

Therefore its Surface Area

[tex]=4\pi\left(2\sqrt{\dfrac{50}{4\pi}}\right)^2\\=4\pi*4*\dfrac{50}{4\pi}}\\\\=200 unit^2[/tex]