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OA ⊥ OC start overline, O, A, end overline, \perp, start overline, O, C, end overline \qquad m \angle BOC = 6x - 6^\circm∠BOC=6x−6 ∘ m, angle, B, O, C, equals, 6, x, minus, 6, degrees \qquad m \angle AOB = 5x + 8^\circm∠AOB=5x+8 ∘ m, angle, A, O, B, equals, 5, x, plus, 8, degrees Find m\angle BOCm∠BOCm, angle, B, O, C:

Respuesta :

Answer:

42 degrees.

Step-by-step explanation:

[tex]\angle BOC+\angle AOB=90^\circ $(Complementary Angles)\\6x - 6^\circ+5x + 8^\circ=90^\circ\\6x+5x-6^\circ+ 8^\circ=90^\circ\\11x+ 2^\circ=90^\circ\\11x=90^\circ-2^\circ\\11x=88^\circ\\$Divide both sides by 11\\x=8^\circ\\$Therefore:\\m\angle BOC=6x - 6^\circ\\=6(8) - 6^\circ\\=48-6\\=42^\circ[/tex]

The measure of angle BOC is 42 degrees.

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Answer:

BOC = 42º

Step-by-step explanation:

Angle BOC is equal to 42 degrees, due to these steps -

1. Create the equation which will result to be -

6x - 6 + 5x + 8 = 90

2. Simplify by adding variables and numbers together -

11x + 2 = 90

3. Subtract 2 from both sides to get -

11x = 88

4. Divide by 11 on both sides to get-

x = 8

5. Substitute x in angle BOC as 8 to get this equation -

6(8) - 6

6. Solve

48 - 6 =

42º

Your final answer for angle BOC is 42º!

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