Answer: 7.6 g of water are required to make 12.6 g of glucose
Explanation:
Moles is calculated by using the formula:
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]{\text {moles of glucose}}=\frac{12.6g}{180g/mol}=0.07moles[/tex]
The balanced chemical equation is:
[tex]6CO_2+6H_2O\rightarrow C_6H_{12}O_6+6O_2[/tex]
According to stoichiometry:
1 mole of glucose is produced by = 6 moles of water
Thus 0.07 moles of glucose is produced by =[tex]\frac{6}{1}\times 0.07=0.42[/tex] moles of water
Mass of water required =[tex]moles\times {\text {Molar mass}}=0.42mol\times 18g/mol=7.6g[/tex]
Thus 7.6 g of water are required to make 12.6 g of glucose
