Answer:
AE = 43.2 units
Step-by-step explanation:
As per the given question image, it can be seen that in the [tex]\triangle ADC \text { and }\triangle AEB :[/tex]
1. [tex]\angle B = \angle C = 90^\circ[/tex]
2. [tex]\angle A[/tex] is common to both the triangles.
3. Two angles are common, so the third angle [tex]\angle E[/tex] is also equal to [tex]\angle D[/tex].
All the three angles in the [tex]\triangle ADC \text { and }\triangle AEB[/tex] are equal to each other, hence the triangles are similar.
As per the property of similar triangles, the ratio of their sides will be equal.
AB : AC = AE : AD
AC = 88 units
BC = 55 units
AB = AC - AB = 33 units
Let side AE = [tex]x[/tex] units
Side AD = AE + ED
So, AD = [tex]x + 72[/tex]
Using the ratio:
[tex]\dfrac{AB}{AC} = \dfrac{AE}{AD}\\\Rightarrow \dfrac{33}{55} = \dfrac{x}{x+72}\\\Rightarrow 55x = 33 \times 72\\\Rightarrow x = \dfrac{3\times 72}{5}\\\Rightarrow x = 43.2\ units[/tex]
So, AE = 43.2 units
